Question

1. The reaction of sulfur with oxygen is shown below.

2S(s) + 3O2(g) → 2SO3(g)

Calculate the mass of sulfur trioxide (in g) produced when 100.0 g of each reactant is present.

A. 100.0

B. 166.8

C. 249.7

D. 200.0

I do know that the molar mass of sulfur trioxide is 80.066 g/mol.

Answer 1

When it says reactant is it referring to 2S(s) + 3O2(g)?

Answer 2

@NvidiaIntely

Answer 3

The molar mass of O2 is 15.999*3=47.997 "3O2(g)"

Answer 4

I thought its referring to 2S(s).

Answer 5

Oh yeah I see what you mean, would that be sulfur?

Answer 6

yes

Answer 7

(i knew there must have been a reason I got that title)

Answer 8

Lol

Answer 9

So then the molar mass would be 32.06 and the *2 = 64.12

Answer 10

I am just confused where I go from there?

Answer 11

Do they mean 100 g of the sulfur?

Answer 12

yes

Answer 13

Do you get it now?

Answer 14

1 gram of sulfur is 0.0124901327951 moles.

Answer 15

So if you take 0.0124901327951*100=1.24901328

Answer 16

Yeah

Answer 17

So 100 grams of Sulfur Trioxide = 1.249013279

Answer 18

Yeah, I think so.

Answer 19

Ok thanks I think I got it :)

Answer 20

So you got the answer to the question?

Answer 21

What is the answer?

Answer 22

Wait....option A is 100.0.

Answer 23

We have to find the mass of sulfur in grams.

Answer 24

try to find limited reagent