Question

A = 3(B + C) solve for B

Answer 1

This is not a test question, the last one was. but i finished it.

Answer 2

We need to isolate B....

\(\huge{A=3(B+C)}\)

We would first divide by 3 to get it to the other side (what we do on one side we do to the other).

\(\huge{\frac{A}{3}=\frac{3}{3}(B+C)}\)

Answer 3

This would simplify to....

\(\huge{\frac{A}{3}=(B+C)}\)

What would we do next?

Answer 4

We would then combine like terms? I'm kinda bad in Algebra 1... sorry

Answer 5

Not quite. In our equation we do not have any like terms...we have three different variables and a real number so no like terms....since we need to isolate B we would subtract C what we do on one side we do to the other....

\(\huge{-C+\frac{A}{3}=B(C-C)} \rightarrow \color{red}{-C+\frac{A}{3}=B}\)

Answer 6

oh okay.... I think I get it now. Thanks!

Answer 7

np ;)