Question

HELP ME PLEASE
Calculate the standard reaction enthalpy for
the reaction
NO2(g) → NO(g) + O(g)
Given:
O2(g) → 2 O(g) ∆H◦ = +498.4 kJ/mol
NO(g) + O3(g) → NO2(g) + O2(g)
∆H◦ = −200 kJ/mol
3O2(g) → 2 O3(g) ∆H◦ = +285.4 kJ/mol
.
1. +413 kJ/mol
2. +592 kJ/mol
3. +93.5 kJ/mol
4. +192 kJ/mol
5. +306 kJ/mol
6. +555 kJ/mol
7. +355 kJ/mol

Answer 1

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