Question

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form.

Answer 1

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\(\Large{By:thomaster}\)

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Answer 2

Heyo:) First we need to find the slope....so lets use slope formula....

\(\huge{\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\rightarrow \frac{10-5}{2-(-3)}}\)

Answer 3

Remember that y=mx+b

slope is calculates as the difference in the y values divided by the x values

The substitute in the values for the variables.

Answer 4

So that would make it 5/5 which is 1

Answer 5

Correct :)

Now we need to find the y-intercept....so we input the first point into the equation to find b....

\(\huge{y=x+b} \rightarrow 5=-3+b\)

What would b equal?

Answer 6

2

Answer 7

Not quite. We need to isolate b so we would add 3 to both sides since it is -3...what we do on one side we do to the other...

\(\huge{5+3=(-3+3)b}\)

Answer 8

Sorry about that i was thinking something else I subtracted 3 from 5 instead of adding it. so b=7

Answer 9

`b=8`. So now we know of the slope and y-intercept....In slope-intercept form the slope is m and the y-intercept is 8....so it would be set up as....

\(\huge{y=x+8}\)

Answer 10

Thank you so much sorry I can't add right now But you did help out a lot.

Answer 11

Np :)