An airplane takes 4 hours to travel a distance of 2400 miles with the wind. The return trip takes 5 hours against the wind. Find the speed of the plane in still air and the speed of the wind.
Last question on my quiz if anyone can help real fast
homework***
try dividing, divide 2400 by 400.
Here are vectors for the velocity of the plane and wind |dw:1475033160937:dw|
So it would be 600 mph for the plane? I thought it would be 600, but kept confusing myself. Especially with the wind speed
So for the wind it would be 600/5
Im assuming
overall velocity on the way there V = P + W Overall on the way back v = P - W
(2400/4 ) mi/h = P + W (2400/5) mi/h = P - W solve that
how fast is the wind?
120 I believe?
alright so plane speed is 600 and wind speed is 120.
Yeah I'm fairly sure 120
Awesome. Thanks guys!
give medal to us then.
Wind W and PLane P 600 = P + W 480 = P - W Solving that gives, P=540, W=60
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