An airplane takes 4 hours to travel a distance of 2400 miles with the wind. The return trip takes 5 hours against the wind. Find the speed of the plane in still air and the speed of the wind.
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OpenStudy (gavin39):
Last question on my quiz if anyone can help real fast
OpenStudy (gavin39):
homework***
OpenStudy (ben00):
try dividing, divide 2400 by 400.
OpenStudy (danjs):
Here are vectors for the velocity of the plane and wind
|dw:1475033160937:dw|
OpenStudy (gavin39):
So it would be 600 mph for the plane? I thought it would be 600, but kept confusing myself. Especially with the wind speed
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OpenStudy (gavin39):
So for the wind it would be 600/5
OpenStudy (gavin39):
Im assuming
OpenStudy (danjs):
overall velocity on the way there
V = P + W
Overall on the way back
v = P - W
OpenStudy (danjs):
(2400/4 ) mi/h = P + W
(2400/5) mi/h = P - W
solve that
OpenStudy (ben00):
how fast is the wind?
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OpenStudy (gavin39):
120 I believe?
OpenStudy (ben00):
alright so plane speed is 600 and wind speed is 120.
OpenStudy (gavin39):
Yeah I'm fairly sure 120
OpenStudy (gavin39):
Awesome. Thanks guys!
OpenStudy (ben00):
give medal to us then.
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OpenStudy (danjs):
Wind W and PLane P
600 = P + W
480 = P - W
Solving that gives, P=540, W=60