Question

What is the vertex of the quadratic function below?

y= 3x^3 - 12x +17

A. (-2, -5)
B. (3, 17)
C. (-3, 17)
D. (2, 5)

Answer 1

I suspect that you mis-typed the equation

ax^2+bx+c=0

Your a value is 3
Your b value is -12
Your c value is 17

x = -b/2a
y= f(-b/2a)

Answer 2

Here it is, I hope this makes better since.

Answer 3

Here is a tutorial to help explain the process

http://www.youtube.com/watch?v=BODGlEl-zWM&t=4m6s

Hope this helps!

Answer 4

sense not since

Answer 5

You can turn that standard form y=ax^2 + bx + c , into a vertex form y=a(x - h)^2 + k
where the vertex is the point (h,k)

Answer 6

y = 3x^2 - 12x + 17
factor 3 from the first 2 terms

y = 3*(x^2 - 4x) + 17
complete the square adding 4 and taking away 3*4=12

y = 3*(x^2 - 4x + 4) - 12 + 17
factor

y = 3*(x - 2)^2 + 5

There is the vertex form, you can see the vertex is (h,k)=(2 , 5)