Question

help?

Answer 1

that question doesn't make sense

Answer 2

Distance formula \[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

Answer 3

yes, but whta do I place in x2 do i put 5 or 2?

Answer 4

is it (2-5)+(2-6)?

Answer 5

X_2=5
X_1=2
Y_2=6
Y_1=2

Answer 6

Then 5-2 = 3 and 6-2=4 how do I square it?

Answer 7

3 = 1.73 and 4 = 2 so I add that? 3.73?

Answer 8

So is the answer 4?

Answer 9

\[\sqrt{(5-2)^2+(6-2)^2}\]

Answer 10

it does not matter which point is first if you use (2,2) as the first point,
then you do 2-5 and 2-6
or you could use (5,6) as the first point,
and do 5-2 and 6-2
in this case you get 3 and 4
now square them and add together 3*3 + 4*4

Answer 11

I agree with @phi.
I would say that.

Answer 12

Is the answer 4 or 5?

Answer 13

what did you get for
3*3 + 4*4
?

Answer 14

52?

Answer 15

What is *? times?

Answer 16

* is how I show "multiply"

Answer 17

So if I square root 52, it is 7.21 and rounding to tenths meaning the answer is 7?

Answer 18

what is 3 squared i.e. 3*3 ?

Answer 19

I'm not following? what? 1.73?

Answer 20

Is the answer 5?

Answer 21

we are following what jite posted up above
\[ \sqrt{(5-2)^2+(6-2)^2} \]
inside the square root we have
\[ 3^2 + 4^2\]
which is the same as
\[ 3 \cdot 3 + 4\cdot 4\]
what is 3 times 3:
\[ 3\cdot 3 \] ?

Answer 22

9

Answer 23

now 4*4 ?

Answer 24

16?

Answer 25

yes,
now we add them
9+16
which is what ?

Answer 26

25.....

Answer 27

in other words
3^2 + 4^2 = 9+16= 25

finally we "take the square root"
what number times itself is 25 ?

Answer 28

5

Answer 29

yes, that means the distance between the two points (2,2) and (5,6) is
\[ \sqrt{(5-2)^2+(6-2)^2}= 5 \]

Answer 30

@phi: simply easy clear
deserve a medal!