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Mathematics 14 Online
OpenStudy (liziekay):

Use the figure below, which shows the unit circle with increments of 0.1 units marked off along the circumference in a counterclockwise direction starting from (1, 0). Estimate θ if cos θ = −0.6 and 0 ≤ θ < 2π. (Enter your answers as a comma-separated list. Round your answers to one decimal place.) θ =___

OpenStudy (liziekay):

OpenStudy (3mar):

May I help?

OpenStudy (liziekay):

Yes! @3mar

OpenStudy (3mar):

The idea is in the definition of cos: \[\cos \theta=\frac{ adj }{ hyp }\] and because the cosine is negative (-0.6), that means theta is in either the second or third quadrant.

OpenStudy (3mar):

Do you follow?

OpenStudy (3mar):

Excuse me. I am busy and due to your lake of response, I am going to leave. Salam.

OpenStudy (liziekay):

Sorry, I didn't see your response..

OpenStudy (liziekay):

Yes, I follow. Exactly what I thought

OpenStudy (3mar):

So what is the next step do you think?

OpenStudy (liziekay):

The next step would be to plug in values for cos. What would be the adjacent and hypotnuse.

OpenStudy (3mar):

and the hyp is always 1 (unit circle with unity radius) then where will you plot -0.6?

OpenStudy (liziekay):

In a quadrant..

OpenStudy (liziekay):

so -.6/1 for cos theta

OpenStudy (3mar):

As we all know, cos is negative in II and III. ok?

OpenStudy (3mar):

"In a quadrant.."???

OpenStudy (liziekay):

It depends on if x is -.6 o if y is -.6...

OpenStudy (liziekay):

I believe it would be in the third quadrant since it's negative

OpenStudy (liziekay):

so cos is .9999451694

OpenStudy (3mar):

and II also.....why not? Is not cos(140)= -ve (for example)?

OpenStudy (liziekay):

that's a possibility

OpenStudy (liziekay):

is cos t=x and sin t= y going to help in this case?

OpenStudy (3mar):

We do all what we know, he did not put a restriction about theta, rather he said \[0<\theta<2\pi\] so every quadrant theta is negative, we accepted.

OpenStudy (liziekay):

Ok, so are we plugging in the values of cos theta into the statement mentioned above?

OpenStudy (liziekay):

cos is .6 divided by 1

OpenStudy (3mar):

\[\cos \theta=\frac{ -0.6 }{ 1 }=-0.6\]

OpenStudy (liziekay):

but cos of (-.6/1) turns out on a calculator as .9999451694

OpenStudy (liziekay):

Is that going to help us in any way?

OpenStudy (3mar):

Please we are now in the graph, don't disturb yourself with the calculator results.

OpenStudy (liziekay):

Ok

OpenStudy (3mar):

Take that pic, please. It would clear a lot.

OpenStudy (liziekay):

I see how you got that

OpenStudy (3mar):

Look at the fugure and tell me where the hypotenuse touches the circle in quadrant II and III?

OpenStudy (liziekay):

the hypotenuse touches 2.2 and about 4.1

OpenStudy (liziekay):

wow, that was quite simple....... I must have not been thinking....... Thank you for spending the past hour helping me (:

OpenStudy (3mar):

Yes, 2.2 and 4.1 (actually it is before 4.1 a little bit, but anyway...)

OpenStudy (liziekay):

Would you be available to help with one more?

OpenStudy (3mar):

Even the past day, I will never be late for any help any time. What you just wrote "the hypotenuse touches 2.2 and about 4.1" is the answer required and you are looking for, simply. Don't distract yourself. Be at the top always.

OpenStudy (liziekay):

Okay! Thank you! I'm not understanding what I'm doing wrong in this problem, let me post a picture of the problem itself.

OpenStudy (3mar):

Ok.

OpenStudy (3mar):

You need " help with one more" now?

OpenStudy (liziekay):

yeah.. Could you help?

OpenStudy (liziekay):

OpenStudy (liziekay):

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OpenStudy (liziekay):

|dw:1475086313361:dw|

OpenStudy (liziekay):

|dw:1475086338561:dw|

OpenStudy (liziekay):

|dw:1475086366570:dw|

OpenStudy (liziekay):

20 divided by three is 6.666667 and that times four is 26.6666667

OpenStudy (liziekay):

26.66 is incorrect....

OpenStudy (3mar):

Really and so busy, can I go now and come back to discuss it after 100 min?

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