Question

Help please?
http://acecontent.apexlearning.com/online/algebra_I_sem_2_c_2016/Unit_4/Lesson_3/Activity_49704/printables/Journal1179723.htm

Answer 1

@1davey29

Answer 2

Which problem(s)?

Answer 3

With all I don't understand how to do this! I am really bad at math lol @1davey29

Answer 4

I would need the video it talks about.

Answer 5

I could get the video but this is the transcript to it of what the say in the video
http://acecontent.apexlearning.com/online/algebra_I_sem_2_c_2016/Unit_4/Lesson_3/Activity_49704/content955473.htm

Answer 6

@1davey29

Answer 7

Do you have the layout of the table you're supposed to complete for #1?

Answer 8

Yeah I already completed that @1davey29

Answer 9

2) You can make the graph for the other two rockets by shifting the functions because they should be in the air for the same amount of time and reach the same heights as they should be the same mass.

Answer 10

So I have to draw the other rockets on the graph ?

Answer 11

I don't think so.
3) The -3.7 moves the rocket's graph over 3.7 units to the right, meaning the rocket reached it's maximum height at 3.7 seconds

Answer 12

4) The 82.4 moves the rocket's graph up 82.4 units, meaning the rocket's maximum height was 82.4 ft.

Answer 13

5) The graph will shift horizontally 3 units to the right as the rocket was launched 3 seconds later.

Answer 14

6) The equation of the first rocket was h(t)=−6(t−3.7)2+82.14, so now we just shift it by 3 to the right, which means subtract 3 from x, to get h(t)=−6(t−6.7)2+82.14.

Answer 15

7) Just like the second rocket, the thirds will shift horizontally by three to the right, but this time from the second rocket's graph, as it was fired three seconds after the second rocket. It will also shift vertically up by 20 as it was fired 20 ft. above the other rockets.

Answer 16

8) The equation of the second rocket was h(t)=−6(t−6.7)^2+82.14, so we shift it right by 3 and up by 20, meaning we subtract three from the x and add 20 to the whole thing, which gives us h(t)=−6(t−9.7)^2+102.14.
*I made a typo in number 6. All the )2's should've been )^2

Answer 17

I don't see the "questions above" for #9.

Answer 18

1. Approximately when is the third rocket launched ?
2. Approximately when does the first rocket land ?
3.what is the approximate interval during which all three rockets are in the air ?
@1davey29

Answer 19

9,1) The third rocket would be launched at 6 seconds, using the graph.
9,2) The first rocket would land at double the time it took to reach it's maximum height, so 3.7*2, or 7.4 seconds.
9.3) The interval would be from the third rocket's launch to the first rocket's landing, so from 6 seconds to 7.4 seconds.

Answer 20

Thank you so much !!! @1davey29

Answer 21

Np, happy to help