urgent help with verticle angle relationships
@Jaynator495
@3mar
Well, I am here
Please don't be angry with me about the last question
The same theory: similar triangles lead to equal corresponding angles BUT I want to see your shared answer It is for yoou, not me, to train yourself.
Okay, so if DB bisects AC, that means it is in the middle, correct? We can also deduct that angle ADB and angle CDB are bothe 90 degrees. Continuing to go off the information that DB is a perpendicular bisector, we can determine that triangle DAB is congruent, or the same as triangle DCB. Based off previous knowledge, we know that a triangle's angles add up to 180 degrees. Taking triangle DAB, we concluded that one angle is 90 degrees, and it was given that another is 60 degrees. If you have 2/3 angles of a triangle, you can find the third. 180 - 90 - 60 = 30 We know that angle ABD is now 30, therefore angle DBC is 30. Now set up an equatiion to find the missing angle in the other triangle. 180 - 90 - 30 = 60 Now remember, this is NOT x. We know that the length is equal to 3x, so set the angle to that and simplify. 60 = 3x Divide both sides by 3 20 = x The value of x is equal to twenty. If you understand how to do it this way and you are aware of all the rules, you can also solve it this way: Angle DAB = 60 = DCB = 3x (We know this because they are congruent triangles) So then take out the angle names 60 = 3x Again, divide. 20 = x Hope this helps!!!😀
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