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Algebra
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for the first one, find \(g(0)=4\times 0+2=2\) then \(f(2)=\frac{1}{2+2}=\frac{1}{4}\)
second one is similar, but start with \(f(0)=\frac{1}{0+2}=\frac{1}{2}\) then find \(g(\frac{1}{2})\)
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we need \(g(3)\) which cannot be seen from the picture
i attached second.
it it clear what \(g(3)\) is from the graph?
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you are looking for \(g(f(1))\) so first, from the graph, what is \(f(1)\)?
here we find \(f(1)\) by locating 1 on the x axis, going up to the graph and finding the y coordinate we see it is 3
so \(f(1)=3\) now we need \(g(3)\)
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so its 4
yes
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\[A=\pi r^2\]so ir \(r=5t+4\) you have \[A=\pi(5t+4)^2\]
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lots of choices here one would be \[\frac{4}{x^2}, x+2\]
last one
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G(x+h)=9-(x+h)^2 G(x)=9-x^2
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