Looking for help with three elementary statistics problems..
The height of women are normally distributed with a mean of 65 inches and a standard deviation of 2.5 inches. The heights of men are also normal with a mean of 70 inches. approximately what percent of women are taller than a man of average height?
Sounds as tho' your random variable here is the DIFFERENCE between the average men's height and the average women's height. I believe you need to find the distribution of this DIFFERENCE and then find the area under the standard normal curve for which this DIFFERENCE is negative (signifying women taller than men). Sorry that I cannot go beyond this point in helping you.
I have this: z= x- 65 over 2.5 -> x= 65 +2.5z x> 70 = 65 +2.5z 2=z or 2.00 which is 0.9772 on the standard normal curve table
Which would turn into 98% correct?
Is that a reasonable answer? Are 98% of women taller than a man of average height? Not in my experience.
What I have typed about is what someone else showed me yesterday who logged off before fully helping me. If its not correct then I need to know so I can start over.
I'd like very much to be of further help to you, but cannot, as I have not dealt with this type of problem for three years now. It's just common sense to reject a result that states that 98% of women are taller than the male of average height. What is the specific topic of the section in your stat book or course that you're studying now?
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