Question

Help Please! :3

Answer 1

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded\[y=\sqrt{4x} , y=\frac{ x^2 }{ 4 }\]

Answer 2

Find V by slicing. (Shells Method)

Answer 3

@zepdrix @Jamierox4ev3r @Jaynator495

Answer 4

V=\[\int\limits_{0}^{4}2 \pi x [\sqrt{4x}-(\frac{ x^2 }{ 4 })]\]

Answer 5

Haha, Yea i got that far. But didnt know what to do next. :P

Answer 6

\[\int\limits_{0}^{4} 2 \pi x (\frac{4 \sqrt{4x} -x^2}{4}) \]
\[\frac{2\pi}{4} \int\limits_{0}^{4} 4 x \sqrt{4x} -x^3\]

Answer 7

Ooooo. But how did you get x^3?

Answer 8

Oh i see, you distributed

Answer 9

whatt whatt

Answer 10

ye :P o^_^o

Answer 11

And then i got....
\[\frac{ \pi }{ 2 } \int\limits_{0}^{4} 8x^{3/2}-x^3\]
Is that right? :D

Answer 12

ye

Answer 13

Aight Cool BEANSS

Answer 14

Got the Answer, Thanks Guys!