Question

Anyone online? I'm desperate for Algebra 2 help!!

Answer 1

same!! maybe we can help each other?

Answer 2

Rational Equations in the Real World: Bake Sale

The school is having a bake sale. The first cupcake you buy is $2, each additional cupcake is $1. Find the cost per cupcake for buying 10, 20, and 50. Write a rational equation for this scenario and then use it to solve. Show all work

**IM NOT LOOKING FOR THE ANSWER I JUST NEED HELP UNDERSTANDING

Answer 3

@Nnesha @IrishBoy123 @Frostbite

Answer 4

http://www.montereyinstitute.org/courses/Algebra1/COURSE_TEXT_RESOURCE/U11_L2_T1_text_final.html
i found a website explaining rational equations if that helps at all?

Answer 5

I understand rational expressions, i just dont understand how to get this problem represented as a rational expression. Ive been to that site earlier today and the time and rate problems dont help explain what i need.

Thank you though

Answer 6

ohh okay. sorry i couldn't be of any help.

Answer 7

@Jaynator495

Answer 8

@zepdrix

Answer 9

Hmm this is kind of weird.
You been learning about sequences?
Because that's how I'm thinking of the problem right now.

Answer 10

not sequences. sorry.
i have a function for it --> f(x) = 2 + (x-1)
and i have tested it out and it works....
the problem is it has to be a rational expression.

Answer 11

@puppyprinc3ss this is the question

Answer 12

Well your expression certainly is rational :)
Rational expressions look like this type of thing: \(\large\rm \dfrac{x+3}{x-2}\)
That type of stuff.

Your expression is: \(\large\rm \dfrac{2+(x-1)}{1}\)
yay rational.

Not sure what else you're trying to do with it :3

Answer 13

so it counts as a rational equation even if there isnt an x in the denominator??

Answer 14

We need to have some sort of polynomial in the numerator and denominator.
The one in the denominator is a polynomial, it's just really simple, 1.

Yaaa it should count :d

Answer 15

do you think it matters if the graph doesnt look like all the other rational equations graphs

Answer 16

Hmm what do all the other ones look like? D:
Maybe I'm missing something..

Answer 17

and theres vertical and horizontal asymptotes that the graph doesnt cover

Answer 18

Ya it's fine :)
Just make sure you don't graph any of the negative numbers.
We can't sell a negative amount of cupcakes.

Answer 19

thank you so much for your help i really appreciate it

Answer 20

you have to pay extra one dollar for first.
so if you buy x cupcakes then cost of each caupcake\[=\frac{ x+1 }{ x }\]