Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (angelax0):

Find g(-3), g(2) and g(5)

OpenStudy (angelax0):

jhonyy9 (jhonyy9):

than you check these given two cases when x not equal 2 g(x) = (-1/3)x^2 +4 and for x=2 g(x) = 4 so in this cases you know easy that g(2) = 4 and on the other cases g(-3) and g(5) just substitute in place of x these given values and make the calculi hope helped

OpenStudy (angelax0):

i got -6 for g(-3) and 2 for (5) is this right?

jhonyy9 (jhonyy9):

please write your work here

OpenStudy (angelax0):

g(-3) = (-1/3)-3^2+4 =-10.33 + 4 = 6.33 ?

jhonyy9 (jhonyy9):

no -3^2 = ? = (-3)(-3) = ?

OpenStudy (angelax0):

-3^2 = 9

jhonyy9 (jhonyy9):

exactly so but there is a sign minus in front of this fraction so will be -9/3 = ?

OpenStudy (angelax0):

so -3?

jhonyy9 (jhonyy9):

yes -3+4 = ?

OpenStudy (angelax0):

1

jhonyy9 (jhonyy9):

sure so not is 6

OpenStudy (angelax0):

so for 5 would you just do 5^2 to get 25 then do 25 + 4?

OpenStudy (angelax0):

or would it be 5/5 to get 1 then do 1+4?

jhonyy9 (jhonyy9):

no - 5^2 ------ +4 = ? 3

OpenStudy (angelax0):

-25 / 3 = -8.33 + 4 = -4.33 ?

jhonyy9 (jhonyy9):

sorry there is exactly 5^2 - ---- +4 = ? 3

jhonyy9 (jhonyy9):

yes -25 ----- +4 = (-25 +4*3)/3 = ? 3

OpenStudy (angelax0):

so it would be -4.33 ?

jhonyy9 (jhonyy9):

g(5) = (-13)/3

OpenStudy (angelax0):

oh so i would leave it at the fraction

jhonyy9 (jhonyy9):

yes this is more elegant

jhonyy9 (jhonyy9):

fractional

OpenStudy (angelax0):

would the negative sign be before the fraction or just on the -13?

jhonyy9 (jhonyy9):

in front of fraction 13 - ----- 3

OpenStudy (angelax0):

thank you

jhonyy9 (jhonyy9):

np welcome and anytime was my pleasure good luck bye bye

OpenStudy (angelax0):

could you help me with another problem?

jhonyy9 (jhonyy9):

post on the open question column and tag me there please

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!