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Chemistry 21 Online
OpenStudy (amyzing179):

Sodium sesquicarbonate decomposes as follows on heating: 2NaHCO3.Na2CO3.nH2O(s) 3Na2CO3(s) + CO2(g) + (2n+1)H2O(g) Hence calculate the value of ‘n’ in the formula NaHCO3.Na2CO3.nH2O if the mass of solid residue of Na2CO3 left after heating is 0.41g and the mass of sodium sesquicarbonate crystals used in the experiment is 2g

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