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What is the value of z for the equation -3 -1 1 3
My guess: 3?
I'm very bad at fractions so I need help badly. x.x
@welshfella Are you good at math? ;o;
There are three fractions in this problem. The two different denominators represented are 4 and 2. What is the lowest common denominator? convert that (1/2)z into its equivalent form using the LCD.
0?
as the lowest common denominator
@mathmale ?
Might be well for you to read up on "lowest common denominator." A denominator of 0 will not "work," because you'd have division by zero, which is not defined. Here's an example: combine the fractions 2/3 and 3/4
Since the denominators 3 and 4 have no common factor, we obtain the LCD by multiplying 3 and 4 together. The LCD is 12. Then 2/3 converts to 8/12 and 3/4 converts to 9/12. The sum is then 17/12. Try again. What is the LCD when the 2 denominators are 2 and 4? Please, please read about LCDs in your textbook, study materials or Internet browser.
2?
Can you divide 2 by 4 and not get a remainder?
No..?
In other words, can you divide 2 by 4 and get an integer quotient (NO fraction)? Right. No. So 2 is not your lowest common denominator. What's the smallest number you can think of that can be divided by 2 and 4 with NO remainder? This is what "LCD" is all about.
By remainder what are you referring to?
Please look up "LCD" in your textbook or online learning materials. You WILL have to know and understand the concept of LCD throughout your math course work. 2 divided into 3 results in a quotient of 1 with a remainder of 1. 23 divided into 45 results in 1 22/45. The 22 is your remainder.
4 divides into 4 with NO remainder (or a zero remainder).
So it would be 4?
Yes, that's right. Your expression has 3 terms. 2 of them already have the LCD (4) as denominator. The 1st does not. You must MODIFY the first term so that its denominator is 4. If you change the denom. in any way, you must perform an identical operation on the numerator. Write out the revised 1st term, please.
(1/4)z = (-3/4) + (1/4)z
?
Good. Since all 3 fractions have the same denoms. now, we can clear the expression of fractions. Just type out the same thing, but leave out the 4 in each denom.
1z = 3 + 1z
On the left side you began with z/2. You can change the form of this fraction, but not the value. Your 1z/4 is not the same as z/2. Mind trying again? Again, the LCD is 4. Your first fraction has the "wrong" denominator: 2. How can you change the fraction so that its denom. is 4 and its overall value is the same as before?
I'm confused.
Why are we finding and using the LCD here? Have you read up on examples in your textbook or online?
I can't find any thing that is useful to me since it's hard to understand.
Unfortunately, most of us have to learn how to learn on our own sooner or later. Even if you have to struggle with the explanation of LCD found in a book, what you learn will be worth it. Take my word for it. I'm deaf and thus have had to learn practically everything from books. And you may need to read an entire section in your textbook to come to a reasonable understanding of the LCD concept.
We use LCD to find the denominator in common with two fractions?
You typed this earlier: (1/4)z = (-3/4) + (1/4)z Actually that should be (1/2)z = (-3/4) + (1/4)z. The 2nd and 3rd fractions are fine as they are; both have the denominator 4. The 1st fraction does not. Therefore you must multiply numerator and denom. both of this fraction so as to obtain the LCD, 4, in the denom. Starting with (1/2)z = (-3/4) + (1/4)z, please change the first term so that its denom. is 4.
I typed that because you told me to change all denominators to the 4 in the equation
Sorry, but I did NOT tell you to do that. I told you that the 2nd and 3rd fractions already have the denominator 4, equal to the LCD, and are fine as they are. The 1st fraction is z/2. Kindly multiply the numerator and den. of this fraction by 2. What do you get?
2/4?
Yes, but what happened to the variable, z?
2/4z?
Yes, but 2z/4 would be much better. 2/4z is ambiguous. If you want to write it that way, then enclose the fraction in parentheses: (2/4)z.
Now you have (2/4)z = (-3/4) + (1/4)z.
Are the denominators all the same?
Yes
That means we're now ready to eliminate the denom. (4) from all 3 fractions. Do that now. Your result?
By eliminate, do I divide the denominator by the numerator on all of the fractions?
Write out (2/4)z = (-3/4) + (1/4)z and then multiply each fraction by 4. No, don't divide. Yes, multiply by 4.
For example: 4*(1/4)z = z
Do I multiply them by 4 by turning them into decimals first..?
There is no reason at all for turning them into decimals. Keep in mind that 4/4 = 1. Multiply each of the 3 terms by 4 and then cancel: (4)(2z/4) = 2z. Going to decimals is not necessary and will not save you time or otherwise help you.
\[4[\frac{ 2z }{ 4 }]=2z\] after this cancellation.
Do the same thing to the remaining 2 fractions.
-3 and 1?
Yes, except that the "z" is missing from the 3rd term. You want From (1/2)z = (-3/4) + (1/4)z. you want 2z = -3 + 1z
Solve this equation for z. Subtract 1z from both sides.
2z = - 3 + 1z -1z = -1z ---------------- answer?
1z = -3?
Yes. Now, drop the '1'. Your result?
(1/2)z = (-3/4) + (1/4)z. 1. Identify the LCD. It is 4. 2. clear fractions by mult. every term by the LCD: 2z = -3 + 1z 3. solve for z: z=-3. End.
z = -3?
Hope you can take notes on our conversation, and that you'll practice problems requiring the LCD.
Thank you very much for the medal! Good luck to you.
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