Complete and balance the following equations:
\[AlBr_3(aq) + Fe(NO_3)_3(aq)-->AlFe + 3Br(NO_3)\] This is what I got on the first one
\[NaOH(aq) + Pb(NO_3)_3(aq) --> Pb(OH)_2 + Na(NO_3)_2\] Here's the second
\[NaOH(aq) + AgC_2H_3O_2(aq) --> AgOH(s) + NaC_2H_3O_2(aq)\] And this is the last one
Please check my work and add the states for the 1st and 2nd equations
They are correct. As for the states, unless they are insoluble (which would be evident using a solubility table or their respective Ksp values) they will be aqueous.
So they are all soluble except Pb(OH)2 which would be (s)?
You know, i totally overlooked the fact that the first one is wrong. You have cation and anions bound to each other. But yes Lead(II)hydroxide is insoluble. Rework through #1
\[AlBr_3(aq) + Fe(NO_3)_3(aq)-->Al(NO_3)_3(aq) + FeBr_3(aq)\]
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