Question

PLEASE HELP I NEED 100% WILL MEDAL!

Answer 1

I need the question, not the medal

Answer 2

its 3 and 4

Answer 3

Ok.

Answer 4

You already know the equations of motion!

Answer 5

I mean, i've been missing school quite a bit because of sickness so, i don't fully understand how to do it

Answer 6

I ask Allah to heal you and be better than before.

Answer 7

well can you help me with this

Answer 8

so who fill in the table?

Answer 9

i did

Answer 10

when?

Answer 11

today

Answer 12

so can you refer to row 3?

Answer 13

i know how to do question one an two but im unclear on how to do 3 and 4

Answer 14

what is the magnitude of g?

Answer 15

Ok
I will help

Answer 16

what is g?
its value at you?

Answer 17

Thank you for the medal!

Answer 18

do you mean 9.8???

Answer 19

i'm so lost

Answer 20

yes, as somewhere they put it as 10 m/s2

Answer 21

step by step In Sha' Allah you will get it

Answer 22

ok ru going to help me and show me how?

Answer 23

Of course.Will not be late for any help.

Answer 24

please, carry on and help me

Answer 25

Take that and see it when I am talking

Answer 26

Are you there?

Answer 27

hey

Answer 28

yes

Answer 29

what does f stand for?

Answer 30

got it?

Answer 31

F stands for the additional force applied to the rock.
I just need its effect to increase the acceleration.
ok?

Answer 32

im trying to find the instantaneous velocity at 4,5, and 6 seconds,

Answer 33

please be with me one by one to hit the final answer later, ok?

Answer 34

@agent0smith can you help???

Answer 35

now (at the third second from falling) what is the accel.?

Answer 36

can you just show me the steps on how to do it, like write it down or something???? find t=4 and ill do the other two

Answer 37

you need 3? or 4?

Answer 38

3 or 4?

Answer 39

ohh my gosh, for #3 it says the acceleration increased by 10m/s^2 after falling for 3 seconds, calculate the instantaneous velocity at t=4, t=5, t=6 seconds and you find the instantaneous velocity for t=4 and show the stepss

Answer 40

we are now at 3
a=9.8+10=19.8 m/s2
you have calculated the v already and it is 30 m/s
then
you have the initial velocity
+
acceleration

now solve for the state 4 as follows
t=1 (as we have a new value for accle.)


for fifth state take t=2 as the previous reason

Answer 41

A change in velocity depends on your acceleration and how long you accelerate for

\[\Delta v = a*t\]
\[v _{2}=v _{1}+a*t\]

a new velocity is equal to the old velocity plus acceleration times time.

Answer 42

im looking for instantaneous

Answer 43

instantaneous = velocity you already have calculated.

Answer 44

This says that the acceleration changes from 10 to 20 at t=3 seconds

For t=0 to t=3
\[v _{2}=v _{1}+10*t\]

for t=3 onwards
\[v _{2}=v _{1}+20*t\]

Answer 45

right before the acceleration goes to 20, the velocity at t=3 is

v = 0 + 10*3 = 30 m/s

Answer 46

For time t is larger than t=3, you use

v = 30 + 20*t

Answer 47

what exactly is the formula for instantaneous velocity

Answer 48

@DanJS

Answer 49

Dan has already included this is his expressions!

Answer 50

ok chill

Answer 51

it is a limit as time goes to zero of change in position x over change in time t

\[\large v=\lim_{\Delta t \rightarrow 0}\frac{ \Delta x }{ \Delta t }=\frac{ dx }{ dt }\]

Answer 52

all the velocities used are considered instantaneous at whatever time t.
t=1 v=10
t=2 v=20

Answer 53

For a constant acceleration, the following holds

Final velocity = initial velocity + acceleration * time

\[\large v _{f}=v _{i}+a*t\]

If the acceleration changes from 10 to 20 at time t=3, then
at t=3 and forwards, the velocity will be what it was at t=3 plus the acceleration 20 times time after t=3

Answer 54

For time t=3, the velocity is v=30, for times after t=3, the velocity is the 30 plus the acceleration times time (t-3)

\[v _{f}=30+20*(t-3)\]