A standard deck of 52 playing cards contains 13 cards in each of four suits: diamonds, hearts, clubs, and spades. Two cards are chosen from the deck at random.

What is the approximate probability of choosing one club and one heart?

0.0588
0.0637
0.1176
0.1275

Question

A standard deck of 52 playing cards contains 13 cards in each of four suits: diamonds, hearts, clubs, and spades. Two cards are chosen from the deck at random.

What is the approximate probability of choosing one club and one heart?

0.0588
0.0637
0.1176
0.1275

kevin · Answer

1 deck has 13 clubs and 13 hearts

So total clubs/total cards x total hearts/total cards

dallascowboys88 · Answer

b

jango_in_dtown · Answer

Let A denote the event of choosing one club. then P(A)=13/52. 
and B denote the event of choosing one heart when one club is already chosen.
Then P(B)=13/51.
Then required probability =2C1*P(A .B)=2*P(A)P(B) =2*(13/52)(13/51)=26/51=0.1275 approx

jango_in_dtown · Answer

2C1 because any of them can be chosen first...