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Mathematics 16 Online
OpenStudy (user123):

What's dy/dx and what's d/dx

OpenStudy (jango_in_dtown):

d/dx is the differential operator ,, also denoted by D. and dy/dx is the slope of the function y=f(x) at the point (x,y)

OpenStudy (user123):

can you elaborate on that

OpenStudy (dumbcow):

d/dx is notation for taking derivative with respect to variable x. It can be applied to any given function. dy/dx is similar but more specific in that it represents the derivative of "y" with respect to x. Where y is a specific function of x, or just another independent variable. When y is a function of x, then dy/dx also represents the slope of y(x) at a given point. In the cases of a function y(x), then d/dx and dy/dx are interchangeable and applied in same way

OpenStudy (tkhunny):

d/dx doesn't mean anything by itself. It needs an argument. dy/dx \(\dfrac{d}{dx}f(x) = \large \frac{df}{dx}\)

OpenStudy (user123):

when solving implicit functions, why do we have to put dy/dx next to the derivative of y terms?

OpenStudy (user123):

it is in respect to x, however the x is not there.

OpenStudy (user123):

and the derivative is already solved, however we're putting the notation "dy/dx" again?

OpenStudy (user123):

@dumbcow @tkhunny

OpenStudy (mathmale):

You might want to share a sample problem; then we could refer to that sample in answering your question.

OpenStudy (mathmale):

Better make a point of learning the significance of the operators d/dx, d/dy, and so on. You'll need to use them often!

OpenStudy (mathmale):

d/dx is the most common "derivative operator."

imqwerty (imqwerty):

this example might help u understand why they put dy/dx after they differentiate the "y" terms with respect to x Suppose we are differentiating x+2y+3 So d(x+2y+3)/dx d(x)/dx + d(2y)/dx +d(3)/dx Here u can write d(2y)/dx like this-d(2y)/dx -> d(2y)/dy x dy/dx ->2dy/dx So d(x)/dx + d(2y)/dx +d(3)/dx =1+2dy/dx+0

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