Question

I will fan and medal,
I have an attachment with 2 problems, If someone could walk me through them

Answer 1

It just says: 2) Lesson 3.09 (2.5 points)


3) Lesson 3.10 (2.5 points)

Answer 2

Copy and paste the questions

Answer 3

give me one moment sorry

Answer 4

ok!

Answer 5

For question #2 you would need to plug in the vertices into the equation....

\(\huge{P=4x+y}\)

Plug in the points `(4,2), (10,2), and (10,14).`

\(\huge{P=4(4) + 2}\)

\(\huge{P=4(10)+2}\)

\(\huge{P=4(10)+14}\)

Whichever has a greater value of P is your maximum value.

Answer 6

ooooooooo thank you!!!!!

Answer 7

No problem :)

To plot the question #3 you can use this site it helps :) calorful.com/graphing/calculator

Answer 8

Wherever the points meet will be your points....you would then apply the same thing we did before :)

Answer 9

so what do you mean where the points meet?

Answer 10

downloaded but can't see the questions.

Answer 11

I meant where ever the lines intersect at it will be your points...

Answer 12

@563blackghost

wait so like (0,40) is in the shaded area of all 4 inequalities, would that work?

Answer 13

Yes (0,40) is one :)

Answer 14

so i just sub in (0,40) into P=2x+2.5y? @563blackghost

Answer 15

Yes :) Though we need to apply all points...

Answer 16

If you click at where they meet you'll be given the point....

Answer 17

That's if you used the website.

Answer 18

all points? so like e at (33.333,16.667)?

Answer 19

Since it is `33.333` it would be \(\Large{33 \frac {1}{3}}\)

Since it is `16.667` it would be \(\Large{16 \frac{2}{3}}\)

Answer 20

But yes that is another correct one :)

Answer 21

Another would be (0,0)....

Answer 22

okie and (44.444,0)?

Answer 23

Yup :) So we have all four points ^.^ Just plug them in and whichever is max is the answer :)

Answer 24

okay thank you so much!!!!

Answer 25

Your very welcome :)

Answer 26

I don't know aljerbra that has a number - or + a number like 5 with no d=4