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Which ordered pairs are solutions to the inequality 4x+y>−64x+y>−6?
Select each correct answer.
(2, 0)
(−1, −1)<----
(−3, 6)<----
(0, −9)
(4, −20)<----
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OpenStudy (weaver):
@Aleah54
OpenStudy (weaver):
@Vuriffy
OpenStudy (weaver):
@Lowkey.S
OpenStudy (lowkey.s):
ummm
OpenStudy (lowkey.s):
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OpenStudy (weaver):
hmm i dont know about that answer lol
OpenStudy (lowkey.s):
idk too lol
OpenStudy (weaver):
Its okay ill tag someone else thanks for trying :)
OpenStudy (weaver):
@razor99
OpenStudy (weaver):
@UnkleRhaukus
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OpenStudy (weaver):
@WhitmoreRad12
OpenStudy (weaver):
@whpalmer4
OpenStudy (weaver):
@girlstudy
OpenStudy (unklerhaukus):
The inequality is
\[\large\boxed{4x+y>−64x+y>−6}\]
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Substituting in the first potential solution \((x,y)=(2,0)\):
\[4(2)+(0)>−64(2)+(0)>−6\]
simplifying
\[8>-128>-6\]
but \(-128\not>-6\) so \((2,0)\) is not a solution to the inequality.
___
Substituting in the second potential solution \((x,y)=(-1,-1)\), we get:
\[4(-1)+(-1)>−64(-1)+(-1)>−6\]
which simplifies to
\[-6>63>-6\]
which is also false, so \((-1,-1)\) is also not a solution to the inequality.