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Mathematics 16 Online
OpenStudy (steve816):

Anybody know the answer to this physics problem? A 300-g mass is attached to the bottom of a vertical spring, pulled downward and then released. The mass moves upward until it causes the spring to compress 5 cm. If the spring constant is 8.8 N/m, what acceleration is the mass experiencing at this position? Basically I wrote m = 0.3 kg d = 0.05m k = 8.8 N/m a = ? I knew that the spring force = 0.05 * 8.8 = 0.44 N I knew that the force of gravity = 0.3 * 9.8 = 2.94 N I knew that the net force = 0.44 N - 2.94 N = -2.5 N I used the equation F=ma -2.5 N = 0.3 kg * a I got a = -8.33 m/s/s But the webassign is saying that it is incorrect :( Please somebody help me!

OpenStudy (jiteshmeghwal9):

the question is asking the acceleration after it compressed the spring by 5 cm

OpenStudy (inkyvoyd):

Can you draw an FBD? Are you sure the spring force and force of gravity are opposite in polarity?

OpenStudy (steve816):

@inkyvoyd Yes, they are opposite @jiteshmeghwal9 So how would I calculate it???

OpenStudy (inkyvoyd):

Why don't you try drawing a picture first?

OpenStudy (steve816):

|dw:1475829768076:dw| Ok now what?

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