A sample of gas occupies a volume of 74.7 mL. As it expands, it does 123.3 J of work on its surroundings at a constant pressure of 783 torr. What is the final volume of the gas?
Are you familiar with the gas laws?
I am not too strong with them
work= -PΔV -123.3 J = -783 torr × (Vfinal - 74.7 mL)
So, \[.157 = (Vfinal - 74.6 mL)\]
\[Vfinal = 74.757\] ?
We have to make some conversions. Torr is not an SI unit.
What would we convert it to?
Right!
we need the units on the left to match the units on the right. so we can convert Joules to L atm.
work= -PΔV -123.3 J = -783 torr × (Vfinal - 74.7 mL) -123.3 × (1L atm)/(101.32 J) = -783 torr × (1atm/760 torr) × (Vfinal -74.7 ml × 1L/1000 mL)
\[1.21694 = -1.03(Vfinal - .0747)\]
Sorry, the first one is negative
\[-1.21694=−1.03(Vfinal−.0747)\]
\[10.89 = (Vfinal - .0747)\] \[Vfinal = 10.965\]
But then we have to convert back to mL, so would it be 10965 mL?
doing this on paper, one minute
You should not round intermediate calculations. Ideally put it in one equation. -123.3 /101.3 = -783 / 760 ( v - 74.7/1000)
I did too when I did it the second time. I put 12.1694 by accident into my calculator
Gotcha, that way it is more accurate
I got 1.255889902 L or 1255.889902 mL which is about 1255.9 mL
Thank you for your help. I'm looking at another problem and it actually makes sense now!
Great :)
Again, thank you for teaching
your welcome
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