Question

what is g(1/x)

Answer 1

Okay Hi, how are you?

Answer 2

\[g(y) = y^2-\frac{ 1 }{ (y+1) }\]

Answer 3

okay what do you need help help with?

Answer 4

here is the question

Answer 5

i'm fine thanks alot you"?

Answer 6

Good. Simplify g (1/x)
g/x

Answer 7

Replace all the y's in \(\large g(y) = y^2-\frac{ 1 }{ (y+1) }\) with 1/x

Answer 8

listen to @agent0smith

Answer 9

\[(\frac{ 1 }{ x })^{2} - \frac{ 1 }{ (\frac{ 1 }{ x } )+1}\]

Answer 10

brb

Answer 11

Now you can simplify it

Answer 12

\[\large g\left( \frac{ 1 }{ x } \right) = \left( \frac{ 1 }{ x } \right)^{2} - \frac{ 1 }{ (\frac{ 1 }{ x } )+1}\]you can simplify by multiplying the top and bottom of the right fraction like so\[\large g\left( \frac{ 1 }{ x } \right) = \frac{ 1 }{ x ^2} - \frac{ 1 }{ \frac{ 1 }{ x } +1}*\frac{ x }{ x }\]

Answer 13

An hour ago you (physicsman) said you'd "be right back." Please keep your word. If your situation changes and you need to log off, please be courteous enough to inform those who are trying to help you.