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OpenStudy (shadowlegendx):
\[9*1 = 9 \times 1 = 9(1) = 9\]
OpenStudy (shadowlegendx):
The many different ways you could write it
OpenStudy (shadowlegendx):
But the final, simplified answer, would be 9.
OpenStudy (helpwithk12):
okay but how
OpenStudy (shadowlegendx):
You don't know how to do 9 times 1?
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OpenStudy (helpwithk12):
no its hard what is 1*1 or 2*1 or even 8*2
OpenStudy (shadowlegendx):
How old are you/what is your grade?
OpenStudy (helpwithk12):
Just thank of it like this you count how many times 1 or any other number is multiplied bye its self like 1*1 so 1*1 is only one because 1
OpenStudy (shadowlegendx):
Can you answer my question?
OpenStudy (helpwithk12):
yes
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OpenStudy (helpwithk12):
whats it
OpenStudy (shadowlegendx):
How old are you/what is your grade?
OpenStudy (helpwithk12):
im 12 grade 6th bye gtg
OpenStudy (shadowlegendx):
lol, goodbye dear troll </3
OpenStudy (mathmale):
1 times any other number equals the other number. 1*5=5, 1*13.2=13.2, and so on.
I'd suggest you make up your own table of multiples of two integers.
1*1=1
1*2=2
1*3=3
and so on.
2*1=2
2*2=4
2*3=6
3*1=3
3*2=6
and so on. You need to learn these well enough so that it's not even necessary for you to think about how to obtain the products...they should come to you automatically.