Why does 2sin(x) * cos(x) = sin (2x)?
It doesn't...?
It doesn't? I'm supposed to prove that it does:
its that one identity
Oh, sorry. I misread the question. My appologies
I read it as = 2sin (x) don't know what I was thinking lol
I typed it as 2sin (x) by accident, I just edited the original question sorry lol
oh, lol. so I'm not going crazy
nah, you aren't. but I'm supposed to prove that it does, but it doesn't make sense to me,
Why not?
Because it goes from 2sin(x)cos(x) to just sin (2x), where did the cos(x) go?
hint* \[\large sin(2x) = sin(x+x)\] What can you do with that?
Replying because I want to know the answer too.
(x + x) is 2x so sin(2x) = sin(2x)
Another hint* Remember the addition formula? Being something along the lines of \(\large sin(A+B) = ?\)
As JohnWeldon said, you can change sin(2x) into sin (x + x) Remember formula sin (A + B) = sin A cos B + cos A sin B
It's still not making sense to me, I've read the addition formula, but none of this was really taught to me by anyone so I don't know any of it
Don't worry about it! So you know there is an addition formula...which as shown above is: \[\large sin(A+B) = sin(A)cos(B) + sin(B)cos(A)\] So if we apply that here... \[\large sin(x+x) = sin(x)cos(x) + sin(x)cos(x)\] and from there.....
OH. I see it. sin (x + x) is just sin (2x) which equals sin(x)cos(x) + sin(x)cos(x). Okay, I finally get it. Thank you!
Exactly! And not a problem!
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