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Mathematics 13 Online
OpenStudy (michaelbp):

anyone know how to do domain of a function?

OpenStudy (michaelbp):

OpenStudy (leenathan):

ik how to get a computer domain and code it that what you mean?

OpenStudy (3mar):

What you picked?

OpenStudy (michaelbp):

im way past that problem now ive gotten most right just by guessing

OpenStudy (3mar):

??

OpenStudy (3mar):

do you know what fog(x) mean?

OpenStudy (michaelbp):

OpenStudy (michaelbp):

just needing the answer im about to leave this class and im almost done

OpenStudy (3mar):

Not recommended to give you a direct answer!

OpenStudy (michaelbp):

well then please help i really need a good grade

OpenStudy (3mar):

I wish you have A+, but try with me, don't let me solve alone!

OpenStudy (michaelbp):

ok

OpenStudy (3mar):

fog means replace every x in f(x) and put g(x) as it is. \[(fog)(x)=6(\sqrt{x-6})-3\]

OpenStudy (3mar):

You decide whatever 3 belongs to the domain of this new function or not!

OpenStudy (3mar):

@michaelbp

OpenStudy (michaelbp):

i dont get it

OpenStudy (3mar):

Where are you stuck?

OpenStudy (michaelbp):

OpenStudy (leenathan):

i see a mod

OpenStudy (michaelbp):

so i plug in x^2-4x for all the x in f(x)

OpenStudy (3mar):

Great You got it!

OpenStudy (michaelbp):

so f(x)=1/x^2-4x

OpenStudy (aravindg):

Just watching :) Good work @3mar @michaelbp Did you understand it clearly?

OpenStudy (3mar):

Correct! But you'd better to use the parentheses to be accurate! \[f(x)=\frac{ 1 }{ x^2-4x }\]

OpenStudy (michaelbp):

so wouldnt it be 3x^2

OpenStudy (michaelbp):

1/3x^2

OpenStudy (3mar):

Why?????????? this is raised to the power 2 and that to the power one!!!!! How do you subtract terms are not in the same bases?

OpenStudy (michaelbp):

well i have to go class is over :/

OpenStudy (mathmale):

Mind explaining your reasoning when you give your version of "domain?" What does "domain" mean to you, and what does it mean to "do domain?"

OpenStudy (3mar):

Question closed! Who are you talking to!?

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