Question

I have a question about the formulas you use to graph a parabola. I was given 4 equations and was told to match those equations to 4 graphs i was given. I feel like I got it right but I was wondering if someone would be so kind and check my answer. Thank you so much. *The question is attached*

Answer 1

My thoughts were that:
Equation A matches up with Graph 1
Equation B matches up with Graph 4
Equation C matches up with Graph 3
Equation D matches up with Graph 2

Answer 2

For the first one

y = x^2 - 6x + 8

when x=0, y=8 , point (0 , 8)

when y=0 , x = 4 or x=2
0 = (x - 4)(x-2)

points (4 , 0) and (2 , 0)

Answer 3

It has y-axis intercept at (0 , 8)
It has x-axis intercept at (4 , 0) and (2 , 0)

The only graph to work for that is Graph 3

Answer 4

so A actually matches up with 3

Answer 5

What about the others?

Answer 6

@DanJS

Answer 7

@ganeshie8 @jabez177

Answer 8

@mathmale

Answer 9

berb, I can be of more help if you'd please share your own work. I like Dan's verbal explanations of what he is doing to match equation with graph. Can you do the same?

Answer 10

The second one is

y = (x - 6)(x +8)
do the same thing, x and y axis intercepts...

(0 , -48)
(6 , 0)
(-8 , 0)

Only Graph 4 works on this one

Answer 11

what would be the y-intercept on graph 4

Answer 12

There need to be concrete reasons for each match. What are your reasons?

@danjs: Time to let berb try explaining the remaining two himself / herself. Thanks.

Answer 13

That intercept has the name "S" and could be written as (0,-s), where s is the vertical distance from origin to point S.

Answer 14

If your read my question and what ive been writing back to @DanJS youll see that i was telling him what i got originally so boi

Answer 15

My suggestion is that you explain how you came to your conclusion about the matches.

Answer 16

@DanJS