Find the distance between the points to the nearest tenth A(-1,5), B(0,4)
Hi there! Welcome to OpenStudy! :) Do you have any ideas as to where to start?
Hi! Thank you! Well, based on my book I see that I have to use the distance formula but when I did the answer didn't come out right :(
Hmm.. Can you show me the work you did so far?
Ok so I put (-1,5) (x1, y2) (0,4) (x2, y2) d=sqrt (0-(-1))^2 + (4-5)^2
(x^2-x^1) + (y^2-y^1)
Plug your values into that formula.
=sqrt(1)^2 + (-1)^2 =sqrt 1+(-1) =0 but thats not right :(
Find the squareroot of 20 for your answer.
Ok let's work this out again, Here's the distance formula \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] We plug in our values \[\huge d=\sqrt{(0-(-1))^2+(4-5)^2}\] Continue from here
It's quite simple when you use the formula since the formula (x^2-x^1) + (y^2-y^1) is very straight forward. (-1^2-0^1)+(5^2-4^1) = 20
From there on you'd find the square root
=sqrt(1)^2 + (-1)^2?
You don't have to solve the formula under the SQRT sign first @Mimijola, you can just solve the equation first then take the solution and get the sqrt
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mimijola =sqrt(1)^2 + (-1)^2? \(\color{#0cbb34}{\text{End of Quote}}\) correct so far continue :)
Mimi I led you to the answer, what is the sqrt of 20?
4.4.....
Yes
4.472136 to be specific.
So that is the answer?
That's incorrect.
My book says 1.4
That's the right answer but do you know how to get it?
No, thats what Im confused about.
Ok let's work this out again, Here's the distance formula \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] We plug in our values \[\huge d=\sqrt{(0-(-1))^2+(4-5)^2}\] Continue from here Bare in mind that 2 minus signs next to each other make a positive \[\huge d=\sqrt{(0+1)^2+(4-5)^2}\] Continue it
Whoa whoa, -1 should come before 0 since -1 is X1 being that it's A
Consider rereading the formula @marziman
d=sqrt 1^2 + (-1)^2?
That good :) So we have \[\huge d=\sqrt{(1)^2+(-1)^2}\]
Keep going!
\[\sqrt{1+(-1)}\]
?
Not quite... -1^2=-1 *-1 =?
0? or 1?
Well we are multiplying so which is it?
1
Good :) so we have \[\huge~\rm~\sqrt{1+1}\] 1+1=?
2
Right?
Yep \[\huge~\rm~\bf~\sqrt{2}=? \]
Yayyyy!! 1.4....
Thank you!!!
May I have your help with another one?
You're welcome :) And sure we can do another one
Ok, thanks! Question: AB has endpoints A(-3,2) and B(3,-2) Find the coordinates of the midpoint AB
Here's the midpoint formula \[\huge~\rm~\frac{ x_2+x_1 }{ 2},\frac{ y_2+y_1 }{ 2 } \] We plug in our values \[\huge~\rm~\frac{ 3+(-3) }{ 2},\frac{ -2+2 }{ 2 } \]
0/2, 0/2?
Well almost what is 0/2
0?
Yep so the coordinates are?
0,0?
Yep :)
Omg Thank you very much! You saved my life :0
You're welcome! :)
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