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How do i take the derivative of this?
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\[f(x)=t+ \frac{ 9 }{ t+1 }+1\]
I got (t-8)/(t+1) which is wrong :/
Okay well lets break it up into three. Lets start with the easier ones. What is the derivative of t? and What is the derivative of 1?
1 and 0
Okay good job. So so far we have that \[f'(x) = 1+\left[ \frac{ ? }{ ? } \right] + 0 \]
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Now to take the derivative of\[\frac{ 9 }{ t+1 }\] We have to use to Quotient Rule. Do you know what that is?
yup and for the 9/t+1 i got \[\frac{ -9t-9 }{ (t+1)^2 }\]
OH WAIT I FIGURED IT OUT
i forgot to take the deriv of the bottom lol silly me :')
Haha. Okay then. :)
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so its just 9/(t+1)^2 for tht. Lol thank you!
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