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Mathematics 15 Online
OpenStudy (iwanttogotostanford):

HELP ASAP PLZ

OpenStudy (iwanttogotostanford):

@mhchen @davejavous

OpenStudy (iwanttogotostanford):

@welshfella

OpenStudy (iwanttogotostanford):

which would be right please help ASAP

OpenStudy (iwanttogotostanford):

please make this as quick as possible please

OpenStudy (davejavous):

The general equation for an elipse is: \[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\] The center of the ellipse is: \[centre=(h,k)\] Compare the general equation above, with the one in the question. What's the value of h and k? Hence, what is the coordinate of the center of the ellipse?

OpenStudy (davejavous):

I am helping. If you want a direct answer you're on the wrong site.

OpenStudy (iwanttogotostanford):

@welshfella please help!

OpenStudy (davejavous):

It's not C. This is what I mean by not giving the answer. You don't understand the question.

OpenStudy (iwanttogotostanford):

@mhchen

OpenStudy (davejavous):

Because you wont accept help. If you want an answer type it into wolfram alpha and graph it there

OpenStudy (davejavous):

Use this site if you want answers

OpenStudy (iwanttogotostanford):

i want help but pease a little faster

OpenStudy (austin.l):

If you just want solutions, use wolfram alpha. Come here if you want to be explained how to get to the answer again on your own. Now the reason why it isn't C is because of the formula that was given earlier. h&k=0 Meaning the center is (0,0) That alone narrows it down to one answer.

OpenStudy (austin.l):

two answers, excuse me. But the formula shows the orientation as the x-axis. Meaning D. For your next question. You need to divide both sides by 18 to get it in the correct form and just use the same equation as before!

OpenStudy (iwanttogotostanford):

I think I got it right but I ws stuck between the answer I have chosen (in blue) and A.

OpenStudy (austin.l):

Aren't the foci along the same axis as the rest of the ellipse?

OpenStudy (iwanttogotostanford):

yes

OpenStudy (iwanttogotostanford):

@Austin.L

OpenStudy (austin.l):

I would say so, yes. D.

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