Question

Help please.

Answer 1

Differential Equations.
\[\frac{ dz }{ dt } + 6e^{t+z} = 0\]

Answer 2

Would it be... \[\frac{ dz }{ dt } = -6e^{t+z}\]
\[\frac{ dz }{ dt } = -6(e^t)(e^z)\]
\[\frac{ dz }{ e^z } = -6e^t dt\]
?

Answer 3

@mathmate

Answer 4

@aaronq

Answer 5

Have you tried integrating both sides?

Answer 6

its right so far

Answer 7

Well I was just trying to see if what i did so far was correct.

Answer 8

After integrating, i got \[\ln|e^z|=-6e^t+C\]
but it was wrong...

Answer 9

no integration of 1/e^z isnt ln|e^z|

Answer 10

Eh....\[\int\limits e^{-z} = -e^{-z}\]

Answer 11

Thanks. xD

Answer 12

bullseye