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Mathematics 14 Online
OpenStudy (dehydrated):

HELP QUICK

OpenStudy (dehydrated):

OpenStudy (dehydrated):

I KNOW THAT Alternate Interior Angles theorem states, if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.

OpenStudy (dehydrated):

@Jaynator495

Directrix (directrix):

In the triangle congruence statement in the proof, Point A corresponds to point C So, the missing pair of alternate interior angles would be: <CAB is congruent to <ACB

OpenStudy (dehydrated):

@Directrix

OpenStudy (dehydrated):

TY SO MUCH

Directrix (directrix):

Hold on. Let me check. I may have mixed the letters.

OpenStudy (dehydrated):

ok

Directrix (directrix):

<DAC is congruent to <BCA Now, to choose that option.

OpenStudy (dehydrated):

these are the only options @directrix ∠ABD ≅ ∠DBC ∠CAD ≅ ∠ACB ∠BDA ≅ ∠BDC ∠CAB ≅ ∠ACB

Directrix (directrix):

I have drawn the figure and marked it up several times and cannot find an answer that equates to: <BCA is congruent to <ADB. I'll draw it out.

Directrix (directrix):

|dw:1476578767653:dw|

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