Question

Is this correct?

http://prntscr.com/cuvs3q

Answer 1

@sweetburger

Answer 2

no, it's exponential.

Answer 3

False.
It is like what blockingthesky said.

Answer 4

@Porticus
An exponential function will always have a power that contains a variable, like \(5^x\), or \(e^{x^2}\), etc. Therefore \(5^2x^2+3x+3\) is NOT an exponential function because the exponents (2) do not contain a variable.
On the other hand, log functions always has a log with a variable as an argument.
For example, 5log(x) is a log function, while \(x^2log(2)\) is not, because the argument of log does not contain a variable.
To go one step further, \(log(2)^x\) is an exponential function, while \(log(x)^2\) is a log function.

Answer 5

Thank you, mathmate!
It is a good illustration!