Mathematics
10 Online
OpenStudy (berbie):
functions question
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OpenStudy (berbie):
@Kainui @imqwerty
OpenStudy (berbie):
@Directrix @Callisto @zepdrix @IrishBoy123
OpenStudy (berbie):
@Kevin
OpenStudy (berbie):
@3mar
OpenStudy (3mar):
Hello!
Will not be late for any help.
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OpenStudy (berbie):
?
OpenStudy (3mar):
What is your question?
OpenStudy (berbie):
Evaluate the function g(f(x)) when f(x)=x^2-3 g(x)=(x+4)/5
OpenStudy (3mar):
That means: replace every x in g(x) with all f(x) instead!
Try this and show me your work please
OpenStudy (berbie):
x^2-3+4/5
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OpenStudy (3mar):
Great!
Can you simplify it a little bit?
OpenStudy (berbie):
\[\frac{ x^2-3+4 }{ 5 }\]
OpenStudy (3mar):
-3+4??
OpenStudy (berbie):
@3mar is this correct
OpenStudy (3mar):
-3+4?
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OpenStudy (3mar):
@berbie
OpenStudy (berbie):
-7
OpenStudy (berbie):
\[\frac{ x^2-7\ }{ 5 }\]
OpenStudy (zzr0ck3r):
-3+4=4-3
OpenStudy (3mar):
Good!
This is the answer of your question.
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OpenStudy (berbie):
-3+4=4-3 or \[\frac{ x^2-7 }{ 5 }\]
OpenStudy (3mar):
not
\[\frac{ x^2-7 }{ 5 }\]
Take care!
OpenStudy (3mar):
It will be
\[\frac{ x^2+1 }{ 5 }\]
OpenStudy (3mar):
Got it?
OpenStudy (3mar):
Thank you for the medal! I appreciate!
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OpenStudy (3mar):
Any more questions?
OpenStudy (berbie):
will you be on tomorrow
OpenStudy (3mar):
I don't exactly!
When will you?
OpenStudy (naka354):
g(f(x)) = g(x^2 - 3) = ((x^2 - 3) + 4)/5
g(x^2 - 3) = (x^2 + 1)/5
OpenStudy (mathmale):
@berbie: Next time, PLEASE post your question immediately. It is not necessary to tag all those people early in your post.
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OpenStudy (berbie):
um @mathmale for your information I posted the question and 10minutes later it disappeared so please mind your own business