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Mathematics 10 Online
OpenStudy (berbie):

functions question

OpenStudy (berbie):

@Kainui @imqwerty

OpenStudy (berbie):

@Directrix @Callisto @zepdrix @IrishBoy123

OpenStudy (berbie):

@Kevin

OpenStudy (berbie):

@3mar

OpenStudy (3mar):

Hello! Will not be late for any help.

OpenStudy (berbie):

?

OpenStudy (3mar):

What is your question?

OpenStudy (berbie):

Evaluate the function g(f(x)) when f(x)=x^2-3 g(x)=(x+4)/5

OpenStudy (3mar):

That means: replace every x in g(x) with all f(x) instead! Try this and show me your work please

OpenStudy (berbie):

x^2-3+4/5

OpenStudy (3mar):

Great! Can you simplify it a little bit?

OpenStudy (berbie):

\[\frac{ x^2-3+4 }{ 5 }\]

OpenStudy (3mar):

-3+4??

OpenStudy (berbie):

@3mar is this correct

OpenStudy (3mar):

-3+4?

OpenStudy (3mar):

@berbie

OpenStudy (berbie):

-7

OpenStudy (berbie):

\[\frac{ x^2-7\ }{ 5 }\]

OpenStudy (zzr0ck3r):

-3+4=4-3

OpenStudy (3mar):

Good! This is the answer of your question.

OpenStudy (berbie):

-3+4=4-3 or \[\frac{ x^2-7 }{ 5 }\]

OpenStudy (3mar):

not \[\frac{ x^2-7 }{ 5 }\] Take care!

OpenStudy (3mar):

It will be \[\frac{ x^2+1 }{ 5 }\]

OpenStudy (3mar):

Got it?

OpenStudy (3mar):

Thank you for the medal! I appreciate!

OpenStudy (3mar):

Any more questions?

OpenStudy (berbie):

will you be on tomorrow

OpenStudy (3mar):

I don't exactly! When will you?

OpenStudy (naka354):

g(f(x)) = g(x^2 - 3) = ((x^2 - 3) + 4)/5 g(x^2 - 3) = (x^2 + 1)/5

OpenStudy (mathmale):

@berbie: Next time, PLEASE post your question immediately. It is not necessary to tag all those people early in your post.

OpenStudy (berbie):

um @mathmale for your information I posted the question and 10minutes later it disappeared so please mind your own business

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