Question

HELP ASAP 2 QUESTIONS

Answer 1

@sooobored @Austin.L

Answer 2

@Nnesha @Directrix

Answer 3

if given \[f(x)=x^{n}\]
the derivative
\[\frac{df(x)}{dx}=f'(x)=nx^{n-1}\]

Answer 4

so the first would be 8?

Answer 5

just by looking and doing it roughly in my head,
i dont think so

Answer 6

what do you think....

Answer 7

\[f(x)=1/x\]
\[f'(x)=-1*x^{-2}\]
if x = -1
then f'(x) =-1

Answer 8

it helps to write down the steps

Answer 9

sorry, forgot to mention
\[f(x)=1/x= x^{-1}\]

Answer 10

ah ok what do you think the solutions are to the 2 would be?

Answer 11

well, you can still apply the derivative power rule that i wrote above for number 2

Answer 12

some other derivative rules, if you dont remember them
given a function f(x)=c*x^n
the derivative
\[f'(x)=c*nx^{n-1}\]

also if f(x)=g(x)+h(x)
then the derivative
\[f'(x)=g'(x)+h'(x)\]

Answer 13

can you just help me find the answer thats how i learn the best honestly... :(

Answer 14

ill help you break it up into simpler problems

what is the derivative of -12x^2 ?

Answer 15

i just thing -8 is the answer to 1

Answer 16

@mathmate

Answer 17

@retirEEd

Answer 18

@3mar need help so glad you're here please help!

Answer 19

I think I did this yesterday for you.

Answer 20

Well, I am here.

Answer 21

For the 1st one : it is -8 CORRECT!

Answer 22

And for the 2nd:
It will be:
\[f(x)=-12x^2+9x\]
\[\frac{ df(x) }{ dx }=\frac{ d }{ dx }(-12x^2)+\frac{ d }{ dx }(9x)\]
\[\frac{ df(x) }{ dx }=(-12)(2)(x^{2-1})+(9)(x^{1-1})=-24x+9\]
then you can put x=6:
\[f'(x)=-24(6)+9=-135\]

Sorry for being late!
Hope that helps

Answer 23

Please, tell me that the answer reaches you and you get satisfied!
Salam!