Question

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Answer 1

I don't know what a "rotating space habitat" is. If the "g" is the same as the acceleration due to gravity, then I guess that you have something rotating with a sort of "angular acceleration equivalent of" 9.8m/s^2 of linear acceleration. 130m from the centre of the acceleration, I guess that you want something to be turning with an acceleration of 9.8. That presumably becomes a "radians per second per second" thing. If v = r omega from circular motion, then angular acceleration is r omega/time. 9.8=130 omega. Omega = about 10/130 = about 1/13 about 0.1 radians per second ("feels nice and slow").
That sounds about right in view of the word "habitat" (you don't want animals going round in too much of a spin ... type of thinking).
Going to 65m which is half of 130m, ?=65x0.1 m/s/s. That drags me to 6.6ish m/s/s
That's my guess. Try to stay out of any spin driers for a while, they go much quicker, I think.
bon chance et bon voyage
http://perendis.webs.com
ps thankfully, the q didn't witter on about centrifugal forces and the like. also maybe the "habitat" in question is some sort of NASA thing ?

Answer 2

Thank you so much for the explanation. I mean, makes sense to me!

Answer 3

Does it ? I'm flabbergasted ! :) :) :)