Question

Find the perimeter of parallelogram ABCD with vertices A(–5, 6), B(2, 6), C(1, –2), and D(8, –2).
I got the answer 28 is this correct?

Answer 1

what are the lengths of the sides?

Answer 2

unknown

Answer 3

right, you calculate those..

Answer 4

I did but I'm not sure if I did it correctly....

Answer 5

AB=?

Answer 6

9

Answer 7

AB=7

Answer 8

CD=7

Answer 9

AC=?

Answer 10

5

Answer 11

AC=10

Answer 12

10+10 +7+7=34

Answer 13

ugh I did it wrong could you explain how you got AB and CD

Answer 14

A and B have the same y-coordinates
AB=5+2

Answer 15

Take the point M=(1,6). The triangle AMC is right triangle
AM=6, MN=8
AC^2= 36+64=100
AC=10

Answer 16

You can also use the distance formula between two point (a,b) and (c,d)
\[
d=\sqrt{(a-c)^2 +(b-d)^2}\]

Answer 17

This will allow you to compute all the sides without using my shortcuts

Answer 18

Good night. I have to go to sleep

Answer 19

The horizontal lengths are easy to see the lengths, from x=-5 to x=2, 7 units
same for the bottom piece, x=8 to x=1 , 7 units
The slanted parts you can make right triangles and use the pythagorean theorem...

Answer 20

Sides 8 and 6