A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week.
No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100
What do you think?
This is a test i have taken a bunch of times but always failed :( but i think it was C
So each child bike is represented by 'c', each adult bike is represented by 'a'. This is about time so.. 4c = building time of child bike 6a = building time of adult bike 120 = total building time allowed 4c + 6a = 120 4c = testing time of child bike 4c = testing time of adult bike 100 = total testing time allowed 4c + 4a = 100 Now it asks for whether 10 child bikes and 12 adult bikes can be built in a week. In order to test this, you have to make it fit BOTH equations. So we test them: First equation: 4(10) + 6(12) <= 120? Second equation: 4(10) + 6(10) <= 100? I put <= because they can be lazy and produce less, but they can't produce more ofc.
So First equation: 40 + 80 <= 120? <-- yes Second equation: 40 + 60 <= 100? <-- yes So then you look at your answer choices, and find the one that matches our 2 equations.
So C then :)