solve the system by elimination please help not sure how to do this
-2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5
Add equation 1 and 3 and then 2 and 3. The x terms are eliminated, leaving two equations in two unknowns, y and z.
The sum of equations 1 and 3 is: 5y+6z=5 The sum of equations 2 and 3 is: 2y+4z=-3
Now solve the remaining equations for y and z. Plug in the solutions for y and z into any of the equations and then solve for the result for x.
solve the result for x. sorry.
I make a mistake in one of the calculations above, sorry. That is what can happen when an 82 year old engages in mental calculations. Have bail out now. For your information the solutions are: {x = 1, y = 1, z = 0}
Can even write correct English at this moment. Bye.
Hello! You want to solve this system of linear equations: -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5 Let's (arbitrarily) elimiinate x first, leaving us with a system in y and z. Add the first and third equations together. What do you get? Add the 2nd and 3rd equations together. What do you get?
5y+6z=5 2y+4z=-3
Plese check that -3. Where did -3 come from?
i just brought it down
Again, add the 2nd and the 3rd equations together. What do you get for your constant on the right side of your result?
would it be 2?
yes. Write out your 2 new equations. Note that x has disappeared, as we wanted it to.
so 5y+6z=5 and 2y+4z=2
very good. Now, we arbitrarily choose to eliminate y. (we could choose to eliminate z if we wanted to). Divide the entire 2nd equation by 2 now, please. Your result?
im confused how do i do that
Your 2nd equation is 2y + 4z = 2 Div it by 2: ----------- = y + ? = ? 2
y+2z=1
Yes. now, we want to eliminate y and find z. first equation is 5y + 6z = 5 Please mult your new 2nd equation by -5 and write the result immediately below your first equation (5y + 6z = 5).
Awaiting your response.
like i said im sloowly getting confused
first equation is 5y + 10z = 5. After you mult. the 2nd equation by -5, you get -5y -6z = -5 Please add these two equations together. 5y-5y=0 (and so on).
so add 5y-5y=0 and -5y-6z=-5?
Combine (or "add") 5y + 10z = 5 and -5y-6z =-5
so y+4z=0
but 5y-5y=0. Try again, pls
what? you said 5y+10z=5 and -5y-6z=-5
Indeed I did say that. What's not clear for you?
5y -5y ----- 0
You should get 4z=0. Solve that for z, please.
z=4?
but 4z=0, and if we divide both sides by 4, we get z=0.
oh okay
soo z=0
yes, indeed.
Now we have to find y and x.
Any idea of how to do that?
do i plug in 0 for x?
You could go back to the original 3 equations and plug in 0 for z (not for x). would you do that now, please?
which one do i plug it in for
Please go back to ALL 3 of the original equations. Let z=0 in each and every one. What 3 equations do you get?
oh so do it for all 3 of them give me a min
Yes, all three of : -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5 plug in 0 for z in 3 different places. What's left is -2x+2y+ 0 =0 -2x-y =-3 2x+3y =5
We want to find x and y. Add the last 2 equations together. Your result?
-2x+2y+3(0)=0 -2x-y+0=-3 2x+3y+3(0)=5
Very good. Add the last 2 equations together now.
so x+2y+0=2
Addition error. Note that 2x-2x = 0. You are just subtracting 2 from 2 (wrong); subtract 2x from 2x. Try again.
2x-2x=0
Tghat's correct, but I had asked you to add together (combine) the last 2 equations.
oh so 2x+2x=4x
-2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5 becomes -2x+2y =0 -2x-y =-3 2x+3y =5 Add the last 2 equations together now.
Note that -2x+2x=0.
yes that is what i said above
So you should have obtained 0x + 2y = 2 (not 0).
Solve 2y = 2 for y, please.
2y/2=2/2 y=1
Yes. Now, z=0, y=1. How would you find the value of x?
now sure
go back to the original 3 equations. Pick any one of those three. type your choice below.
2x+3y+3z=5
Now let y=1 and z=0. What do you get?
so 2x+3(1)+3(0)=5
2x+3+0=5
Indeed. simplify that. find the value of x.
3+0=3 2x+3=5
2x+3-3=5-3
You must solve for x. 2x+3=5. Find x.
2x=2 x=1
correct. x=1, y=1, z=0 Go back to the beginning and pick another (different) equation. Your choice.
-2x+2y+3z=0
now let x=1, y=1 and z=0. What happens?
so -2(1)+2(1)+3(0)=0
what is -2+2?
0
what is 0+3(0)?
0
So, has your equation become true or not? 0=0??
true
So we have solved this system of linear equations. using the method of elimination. Any questions?
wow thank you so much for you help i really appreciate it thank you so much!!!:)
My pleasure!! Feels so nice to be appreciated. Good luck! See you again.
Hope your Song of the Soul is sweet music.
ab-soul-ty is
:)
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