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Mathematics 10 Online
OpenStudy (katecc379):

?

OpenStudy (katecc379):

OpenStudy (katecc379):

@jabez177

OpenStudy (katecc379):

@mathmale

OpenStudy (mathmate):

hint: use kinematics equation v1=v0+at solve for t=(v1-v0)/a where a=g=-32.2 ft/s^2

OpenStudy (katecc379):

still confused idk what else to plug in

OpenStudy (mathmate):

what else are you given? the usual notations kinematics is v0=initial velocity v1=final velocity. here we take the coordinate system as positive upwards.

OpenStudy (katecc379):

so initial is 130?

OpenStudy (mathmate):

exactly! Keep going.

OpenStudy (katecc379):

t = -130/-32.2?

OpenStudy (katecc379):

4?

OpenStudy (mathmate):

yes, that's right numerically. You're missing something.

OpenStudy (katecc379):

what

OpenStudy (katecc379):

the negatives cancel out

OpenStudy (mathmate):

Hint: Reread the question to check what was asked for.

OpenStudy (katecc379):

the seconds part?

OpenStudy (mathmate):

Yes, what does it ask for?

OpenStudy (katecc379):

seconds

OpenStudy (katecc379):

max

OpenStudy (mathmate):

Well, in physics (and any science), a numerical answer must be accompanied by the units to be correct. 4 seconds could be 1/15 minute, or 1/900 hour, etc.

OpenStudy (katecc379):

okay i got it

OpenStudy (mathmate):

Good! :)

OpenStudy (katecc379):

????? i hate these omg im lost

OpenStudy (katecc379):

@mathmate

OpenStudy (mathmate):

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