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OpenStudy (katecc379):
OpenStudy (katecc379):
@jabez177
OpenStudy (katecc379):
@mathmale
OpenStudy (mathmate):
hint:
use kinematics equation
v1=v0+at
solve for t=(v1-v0)/a
where a=g=-32.2 ft/s^2
OpenStudy (katecc379):
still confused idk what else to plug in
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OpenStudy (mathmate):
what else are you given?
the usual notations kinematics is
v0=initial velocity
v1=final velocity.
here we take the coordinate system as positive upwards.
OpenStudy (katecc379):
so initial is 130?
OpenStudy (mathmate):
exactly! Keep going.
OpenStudy (katecc379):
t = -130/-32.2?
OpenStudy (katecc379):
4?
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OpenStudy (mathmate):
yes, that's right numerically. You're missing something.
OpenStudy (katecc379):
what
OpenStudy (katecc379):
the negatives cancel out
OpenStudy (mathmate):
Hint: Reread the question to check what was asked for.
OpenStudy (katecc379):
the seconds part?
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OpenStudy (mathmate):
Yes, what does it ask for?
OpenStudy (katecc379):
seconds
OpenStudy (katecc379):
max
OpenStudy (mathmate):
Well, in physics (and any science), a numerical answer must be accompanied by the units to be correct.
4 seconds could be 1/15 minute, or 1/900 hour, etc.
OpenStudy (katecc379):
okay i got it
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OpenStudy (mathmate):
Good! :)
OpenStudy (katecc379):
????? i hate these omg im lost
OpenStudy (katecc379):
@mathmate
OpenStudy (mathmate):
Please make a new post so others have a chance to help you too!