Question

help

Answer 1

@mathmate

Answer 2

Can you explain to me (in words) what the question is telling you, and what does the question want?

Answer 3

how will the wind affect the runners time

Answer 4

what is the formula/equation for?

Answer 5

change in time

Answer 6

yes, if the wind is helping (tail wind), then t will come out positive.
If the wind is opposing the runner, then t will come out negative.
The question is murky on the definition of units (a big no no for math/physics questions), but we have to assume that t is in seconds, and s in m/s.
What else does the question tell you?

Answer 7

not really anything hes running 200m

Answer 8

Actually the 200m does not affect your answer, since it is all built into the equation they supply you.
However, they told you the speed is s=5 m/s.
They need to find t.
So together with the given equation, you have everything you need to find t.

Answer 9

okay so....lol i suck

Answer 10

I have to go. So please complete this and post your answer for a check.
I will look at it when I come back perhaps tomorrow morning.
Good luck! :)

Answer 11

@SolomonZelman

Answer 12

@AloneS

Answer 13

Ok, so what you have a is a function
(I'll change my notation a little, if you don't mind)

\(\color{black}{\displaystyle}{t(s)=0.0119s^2-0.308s-0.0003}\).

\(s\) - denotes the speed ((the average speed)) of the runner
\(t(s)\) - denotes the CHANGE in the finishing time, provided that the runner goes with the speed s.

Answer 14

So, basically, if the runner's speed was \(s=1~{\rm meter/second}\), then the change in the finishing time would be:

\(t(\color{red}{1})=0.0119\color{red}{\times 1}^2-0.308\color{red}{\times 1}-0.0003=-0.2964~{\rm seconds}\)

Answer 15

You have to do precisely the same thing, with an exception that you are asked to determine the change in the finishing time (not when s=1 meter/second, but) when s=5 meters/seconds.

(That is, you will have to plug in \(\color{blue}{s=5}\) into \(s(t)\).)

Answer 16

bye