Question

how do I draw this
A quadrilateral has vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4). Quadrilateral ABCD is a...... If the vertex C(11, -1) were shifted to the point C′(11, 1), quadrilateral ABC′D would be a.....

Answer 1

part 1.
A. is a parallelogram with nonperpendicular and noncongruent adjacent sides
B. trapezoid with exactly one pair of parallel sides
C. rectangle with noncongruent adjacent sides
D. rhombus with nonperpendicular adjacent sides .

part 2
A. parallelogram with nonperpendicular adjacent sides
B. kite
C. square
D. rhombus with nonperpendicular adjacent sides .

Answer 2

Part1
Compute the distances AB, BC, CD, CA
If they are equal what Can you conclude?

Answer 3

Part1
Compute the slopes of AB, BC,CD, DA and see what you can get.

Answer 4

if they are equal then its a square?

Answer 5

\[
AB=\sqrt{(-4+7)^2+(9-11)^2}=\sqrt{13}
\]
Do the same for the rest

Answer 6

No, we can only conclude that it is rhombus. If in addition you can show that one of the angles is 90 degrees, then it would be a circle

Answer 7

I do the slope of AB and you do the rest.
\[
s_{AB}=\frac{-7+4}
{11-9}=-\frac32
\]

Answer 8

Do them and let us discuss what you can conclude

Answer 9

I got AC= 8 BC= 3 CD=3 AD= sqrt13

Answer 10

All of the sides are equal to
\[
\sqrt{13}
\]

Answer 11

im doing the slope now

Answer 12

See the graph

Answer 13

wait when you add them they equal sqrt13 or all of them are sqrt13

Answer 14

Every side is equal \( \sqrt{13}\)