Solve and explain how you got your answer. q + 12 – 2(q – 22) > 0 Help me solve this guys. I have tried to look for something that explains it, but nothing does. Only gives me the final answer, which I don't need.
It's an inequality equation, so lets solve LHS q + 12 – 2(q – 22) > 0 parenthesis first q+12-2q+44>0 Simpify 56-q>0 take q to RHS 56>q 0r q<56 ie, q is less than 56
So, how did you get the 44? You just multiplied the 22 by 2?
Wait nvm. I'm silly.
What happens after that though? Such as with the simplifying portion
We multiply what is outside of a parenthesis to inside of parenthesis to simply.
Wait. you just add the 12 to the 44 and then bring the q's together? Getting rid of the 2 in the process, giving me 56>q
let me make explain simplifying portion, q+12+(-2)*(q-22) q+12+(-2q+(-2)(-22)) q+12+(-2q+44) q+12-2q+44 From here combine like terms q-2q+12+44 -q+56 or 56-q>0
Okay I get it. Thanks for the help. Sorry for being a bit of a derp there.
we will use to simplify expressions, something called "Order of Operations": Parenthesis (Grouping) Exponents Multiply and Divide (Left to Right) Add and Subtract (Left to Right) Often we use the word PEMDAS to remember the order of operations.
Yea, I remember that. I just wasn't thinking right. I'm going to give you a medal and a fan though for the help. Thanks again
NP :)
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