Physics
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OpenStudy (ny,ny):
If you brake your car with constant acceleration and your initial speed was 12 m/s, what is your average speed during breaking?
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OpenStudy (mhchen):
So average speed is change in speed over change in time
OpenStudy (mhchen):
um.....are you given anything else?
OpenStudy (mhchen):
or are you supposed to make accerlation a variable?
OpenStudy (ny,ny):
Im not given anything else.
OpenStudy (mhchen):
dangit, so that's a variable for time and acceleration then...
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OpenStudy (mhchen):
So Final speed = initial speed + accerlation*time
OpenStudy (mhchen):
Final speed is 0.
0 = 12m/s + a*t
OpenStudy (mhchen):
Change in speed is 12m/s
OpenStudy (mhchen):
change in time is t
OpenStudy (mhchen):
could we write it as (12/t)m/s
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OpenStudy (ny,ny):
Yeah I guess?
OpenStudy (mhchen):
Yeah, we'd have to subsitute a variable for time.
OpenStudy (ny,ny):
or -12
OpenStudy (mhchen):
-12/a
OpenStudy (ny,ny):
yes.
so since theres no time given, I should just leave it like that I think?
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OpenStudy (mhchen):
Yeah. Maybe write t as (-12/a) seconds as well just to be safe.
OpenStudy (mhchen):
wouldn't that be -1a m/s ? :o
OpenStudy (ny,ny):
uhh.
Sorry what? lol
OpenStudy (mhchen):
So if change in velocity is 12m/s
And change in time is (-12/a) seconds
OpenStudy (mhchen):
\[\frac{ 12m/s }{ (-12/a )s}\]
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OpenStudy (mhchen):
The a would go to the numerator, and it simplifies to -1
OpenStudy (ny,ny):
Thats true.
OpenStudy (ny,ny):
Would you say that the average speed is -a then?
OpenStudy (mhchen):
yah
OpenStudy (ny,ny):
Alright, thank you :)