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Physics 15 Online
OpenStudy (ny,ny):

If you brake your car with constant acceleration and your initial speed was 12 m/s, what is your average speed during breaking?

OpenStudy (mhchen):

So average speed is change in speed over change in time

OpenStudy (mhchen):

um.....are you given anything else?

OpenStudy (mhchen):

or are you supposed to make accerlation a variable?

OpenStudy (ny,ny):

Im not given anything else.

OpenStudy (mhchen):

dangit, so that's a variable for time and acceleration then...

OpenStudy (mhchen):

So Final speed = initial speed + accerlation*time

OpenStudy (mhchen):

Final speed is 0. 0 = 12m/s + a*t

OpenStudy (mhchen):

Change in speed is 12m/s

OpenStudy (mhchen):

change in time is t

OpenStudy (mhchen):

could we write it as (12/t)m/s

OpenStudy (ny,ny):

Yeah I guess?

OpenStudy (mhchen):

Yeah, we'd have to subsitute a variable for time.

OpenStudy (ny,ny):

or -12

OpenStudy (mhchen):

-12/a

OpenStudy (ny,ny):

yes. so since theres no time given, I should just leave it like that I think?

OpenStudy (mhchen):

Yeah. Maybe write t as (-12/a) seconds as well just to be safe.

OpenStudy (mhchen):

wouldn't that be -1a m/s ? :o

OpenStudy (ny,ny):

uhh. Sorry what? lol

OpenStudy (mhchen):

So if change in velocity is 12m/s And change in time is (-12/a) seconds

OpenStudy (mhchen):

\[\frac{ 12m/s }{ (-12/a )s}\]

OpenStudy (mhchen):

The a would go to the numerator, and it simplifies to -1

OpenStudy (ny,ny):

Thats true.

OpenStudy (ny,ny):

Would you say that the average speed is -a then?

OpenStudy (mhchen):

yah

OpenStudy (ny,ny):

Alright, thank you :)

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