Question

Doing a chemistry Lab in college and am a little confused in this. What is the concentration of the resulting solution, where 10 mL of the solute was pipetted from stock (0.2M) solution to make 50 mL of a diluted NaOH solution? I already know Concentration (Molarity)=moles of solute(mol)/liters of solution(L). Question is how do I find moles of solute and liters of solution to find M. The question later asks in subsequent questions asking for (1) mass of NaOh that should be in the solution, (2) how many hydroxide ions (OH) are present in this solution and (3) what percent of the mass of NaOH w

Answer 1

for calculations of dilutions as in this case you can use the handy equation
C1 x V1 = C2 x V2

where
C1 = initial concentration
C2 = final concentration
V1 = initial volume
V2 = final volume

C2= C1 x V1 / V2