Can someone help me solve inequalities
|5-m| >or equal to 7
Can someone help explain this to me??
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OpenStudy (blanablas):
I can help explain
OpenStudy (blanablas):
You understand absolute value and inequalities, right?
OpenStudy (8bitfox):
yes for example
|-2| =2 |3| = 3
no matter what its sign is right?
OpenStudy (blanablas):
yes
OpenStudy (blanablas):
so for every value in there, it must always be greater than 7
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OpenStudy (blanablas):
are you graphing this?
OpenStudy (8bitfox):
what do you mean by graphing?
OpenStudy (blanablas):
Did they ask you to graph it, or is this the entire question
OpenStudy (blanablas):
inequalites can be graphed
OpenStudy (blanablas):
but i'll go ahead and show u how to solve it
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OpenStudy (blanablas):
so absolute values don't have a real opposite, like addition and subtraction for example
OpenStudy (blanablas):
so you just ignore them really
OpenStudy (8bitfox):
Yeah they do
OpenStudy (blanablas):
they do?
i think i'm having a brain fart here
OpenStudy (8bitfox):
one second
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OpenStudy (blanablas):
ok
OpenStudy (blanablas):
Actually, thinking about this equation
OpenStudy (blanablas):
every value for x < -2 and x > 12 works
OpenStudy (blanablas):
so there's a break in the line, and I never remember doing that
OpenStudy (8bitfox):
They ask me to state the equation or inequality as a disjunction or conjuction then solve it and graph it
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OpenStudy (blanablas):
OH
i remember
OpenStudy (blanablas):
its a disjunction
OpenStudy (blanablas):
to solve it, you can use the +/- sign
OpenStudy (blanablas):
solve for m - 5 and -m + 5
OpenStudy (blanablas):
basically flipping the signs in the second one
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OpenStudy (blanablas):
solving for m - 5, it's m >/= 12
solving for -m + 5, it's
-m < 2
m = -2
OpenStudy (blanablas):
made a typo, i meant m>/=-2
OpenStudy (blanablas):
and when you flip the signs, always turn the inequality sign around
OpenStudy (blanablas):
So to graph it
OpenStudy (blanablas):
there are two lines drawn
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OpenStudy (blanablas):
one for -m + 5 < 7 and one for m - 5 > 7
OpenStudy (blanablas):
the line will be a solid one, not dashed as it's a </= sign
OpenStudy (8bitfox):
okay give me a second im trying to grasp all of this
OpenStudy (blanablas):
do i need to explain the graph?
OpenStudy (blanablas):
Ok, ask if you need help
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OpenStudy (blanablas):
brb, need to submit a test i'm taking
OpenStudy (blanablas):
few seconds
OpenStudy (8bitfox):
so for example FI have |5-m| >or equal to 7 FIRST I change that to
|5-m| >/ 7 AND |5-m| \< 7 correct?
OpenStudy (8bitfox):
Then wouldn't I have to add 5 to both sides??
OpenStudy (blanablas):
back
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OpenStudy (8bitfox):
oops wait hold on
I did that for the wrong inequality thats for less than
OpenStudy (blanablas):
Ok, so m-5>= 7, and -m+5 =<7
OpenStudy (blanablas):
Without it, it would be a regular inequality
OpenStudy (blanablas):
I'll list the steps for solving both equations
OpenStudy (blanablas):
For |m-5| >= 7:
|m| >= 12, but it should be written as m >= 12
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OpenStudy (blanablas):
what i did there is add 5 to both sides
OpenStudy (blanablas):
For |-m+5| < 7:
|-m| < 2 (-5 both sides)
|m| < -2 (multiplied by -1)
OpenStudy (blanablas):
i'm just going to delete the spam omments and explain it all in one mega-comment
OpenStudy (8bitfox):
im so confused @~@
OpenStudy (blanablas):
yeah i'm sorry
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OpenStudy (blanablas):
Ok here goes
OpenStudy (blanablas):
To solve an inequality with an absolute value sign, you must solve the original and inverted form of it
OpenStudy (blanablas):
The original, in this case, is |m-5| >= 7
OpenStudy (blanablas):
the inverted is multiplying the whole left side by -1
OpenStudy (blanablas):
so |-m+5| <= 7 (and flipping the inequality sign)
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OpenStudy (blanablas):
Then, to make things simple, just take away the absolute value signs and solve for m
OpenStudy (8bitfox):
first why do yo you multiply it by -1 (sorry im just trying me best to undertand this step by step
OpenStudy (blanablas):
because absolute values don't care about negatives
OpenStudy (8bitfox):
alright
OpenStudy (blanablas):
if m was -2, it would solve to
|-2 -5| = 7
|-7| = 7
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OpenStudy (blanablas):
that's why
OpenStudy (blanablas):
so solving the original, we get:
|m-5| >=7
|m| >= 12 (add 5 both sides)
OpenStudy (blanablas):
and the inverted:
-m + 5 <= 7
-m=2 (subtract 5 both sides)
m=2(multiply by -1)
OpenStudy (blanablas):
Now for graphing it
OpenStudy (blanablas):
Because m >= 12 OR m<=-2, it is a disjunction
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OpenStudy (blanablas):
or = disjunction
OpenStudy (blanablas):
What you do here is you remove the inequality sign for both the original and inverted equation, and replace them with a = sign
OpenStudy (blanablas):
so you can have the lines for your graph
there are going to be two lines, you shade in a certain part of them
OpenStudy (blanablas):
wait a minute, this is a 1-variable equation
OpenStudy (blanablas):
you can only plot it on a number line
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OpenStudy (blanablas):
if they say to graph it, then somethings wrong
OpenStudy (blanablas):
to graph this, just put points at -2 and 12 on a number line (make sure they are filled in dots because of the >= sign) and draw lines going outwards
OpenStudy (blanablas):
and that's it
OpenStudy (blanablas):
sorry for confusing you at first
OpenStudy (8bitfox):
let me check the paper again
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OpenStudy (blanablas):
ok
OpenStudy (8bitfox):
and don't worry about it
thats fine
OpenStudy (blanablas):
if they say to graph it, they're wrong, just draw a number line and inform whoever gave it to you of their mistake
OpenStudy (blanablas):
unless by graph they mean graph a number line which sounds weird
OpenStudy (8bitfox):
they don't really explain it they just say to graph it, don't worry about it I'll talk to them and explain but thank you anyway for helping with this question
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