this is a picture of my book, how did he get that for part a http://prntscr.com/cwv21g
\[\frac{ 2x }{ x^2 -4 } +\frac{ 1 }{ x(x-2 }-\frac{ 1 }{ x-2 }\]
and the supposed answer is \[\frac{ x+1 }{ x( x+2)}\]
the farthest i got was \[\frac{ x^2 -x+2}{ x(x-2)(x+2) }\]
im past that already
I don't know how you got to where you are. Did you rewrite the first term as: 2x² ------------ x (x+2)(x-2)
Did you rewrite the second term as: (x+2) ------------------------ x (x+2)(x-2)
yes, then
I found the LCD and it was x(x-2)(x+2)
Did you write the third term as: x(x+2) ----------------- x (x+2)(x-2)
yes
the second was x+2 --- x(x-2)(x+2)
2x² + (x+2) - x(x+2) ______________________ x (x+2)(x-2)
and expand the numerator
the numerator becomes 2x^2 +x+2-x^2 -2x
and then x^2 -x +2
x² - x + 2 ---------- x (x+2)(x-2)
yup
but the book
Will this factor: x² - x + 2
no
There is a sign problem somewhere. I don't know if it is a book typo or an error I made.
i think book typo, i just checked this website https://www.symbolab.com/solver/equation-calculator/%5Cfrac%7B2x%7D%7Bx%5E%7B2%7D-4%7D%2B%5Cfrac%7B1%7D%7Bx(x-2)%7D-%5Cfrac%7B1%7D%7Bx-2%7D/?or=dym
I ran the problem through WolframAlpha and got the answer we did: http://www.wolframalpha.com/input/?i=(2x)%2F(x%5E2+-4)+%2B+1%2F(x(x-2))+-+1%2F(x-2)+%3D
Yes. A typo is at play. Did you work the second example?
yeah the second example is good
Okay.
thanks
You are welcome. Your algebra skills are good.
thanks
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